200-10x/((20-x)^2+24^2)1/2=6

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Solution for 200-10x/((20-x)^2+24^2)1/2=6 equation: 


D( x )

((20-x)^2+24^2)^1 = 0

((20-x)^2+24^2)^1 = 0

((20-x)^2+24^2)^1 = 0

(20-x)^2+24^2 = 0

(20-x)^2+576 = 0

(20-x)^2+576 = 0

x^2-40*x+976 = 0

x^2-40*x+976 = 0

x^2-40*x+976 = 0

DELTA = (-40)^2-(1*4*976)

DELTA = -2304

DELTA < 0

1 = 0

1 = 0

x in (-oo:+oo)

200-(((10*x)/(((20-x)^2+24^2)^1))/2) = 6 // - 6

200-(((10*x)/(((20-x)^2+24^2)^1))/2)-6 = 0

200-5*x*((20-x)^2+24^2)^-1-6 = 0

(-5*x)/((20-x)^2+576)-6+200 = 0

(20-x)^2+576 = 0

(20-x)^2+576 = 0

(20-x)^2+576 = 0

x^2-40*x+976 = 0

x^2-40*x+976 = 0

x^2-40*x+976 = 0

DELTA = (-40)^2-(1*4*976)

DELTA = -2304

DELTA < 0

1 = 0

1 = 0

200-5*x-6 = 0

200-5*x-6 = 0

194-5*x = 0

194-5*x = 0

194-5*x = 0 // - 194

-5*x = -194 // : -5

x = -194/(-5)

x = 194/5

x = 194/5

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